Own-Cupcake7586

Own-Cupcake7586 t1_j6eidx7 wrote

One is the default for the functions. If you’re looking for the output to be a length, you need to scale them accordingly. For example, for a circle of radius 3, you’d write:

3 x (sin^2 + cos^2 ) = 3(x1)

The definition of the equation stays the same, but both sides get scaled evenly.

Hope that helps.

3

Own-Cupcake7586 t1_j6dkkdd wrote

The short answer is that the technology of the odometer pre-dates any ability to track the speed/ torque usage of the vehicle. As such, the “miles only” odometer is the de facto standard. Modern cars could have more meaningful metrics, but there is no requirement to add such a thing, so manufacturers don’t bother.

9

Own-Cupcake7586 t1_j46elij wrote

Australian flies to America and immediately gets in a fight. Next day he’s laid up in the hospital, bruised and battered. Doctor comes in, looks at his chart.

Doc says “What, did you come here just to die?”

Aussie replies “Nah, mate, got here yesterday.”

75

Own-Cupcake7586 t1_ix3zaaj wrote

It’s an arbitrary thing. We use base ten, meaning we use ten digits, 0 - 9. When we reach 9, we roll over to 1 ten and 0 ones, or 10. Like another user pointed out, this may be a result of our number of fingers. But we could use base twelve. Or eight. Or seven.

So the answer to your question is: because some old dead dudes decided to start, and we kept it going.

16

Own-Cupcake7586 t1_iuioia0 wrote

Because the freezing point is at a different temperature on the two scales. If both used 0 for freezing, then half of one would be half the other. But because of the offset, they do not stay linear with each other.

In other words, if (degF = A x degC), you would see the kind of relationship you posted. But instead, (degF = A x degC + B), where A= 1.8 and B = 32. That “+ B” throws everything off.

2

Own-Cupcake7586 t1_iuicyqw wrote

Basically, any energy has to go somewhere. If you hit a billiard ball into another, the second ball will travel away from the first, and the total energy after the hit will be about the same as before (minus friction and other losses). Pushing someone forward will tend to push you backward, etc.

If you thinking of one of those swinging ball toys, Newton’s Cradle, this law is what you see when you pull back one ball and let it go. The action (one ball swinging into the group) has an equal and opposite reaction (one ball swinging out of the group). Pull back two balls and let them go, and now two balls swing out the other side.

Hope that helps.

0