Specifically, putting a damaged battery under a heavy load will cause the output voltage of the battery to drop below the threshold voltage required to make a diode actually pass current. Effectively, this is the same as taking the battery out of the circuit momentarily and the device starts up from a power failure when the voltage returns to the breakdown threshold.
Ok-Yogurt-2743 t1_j1erqlb wrote
Reply to What caused this? by TrashAtEverything_
Specifically, putting a damaged battery under a heavy load will cause the output voltage of the battery to drop below the threshold voltage required to make a diode actually pass current. Effectively, this is the same as taking the battery out of the circuit momentarily and the device starts up from a power failure when the voltage returns to the breakdown threshold.
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